1/2(z-1)-(z-3)=1/3[z+3]+1/2

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Solution for 1/2(z-1)-(z-3)=1/3[z+3]+1/2 equation:


1/2(z-1)-(z-3)=1/3[z+3]+1/2

We simplify the equation to the form, which is simple to understand 
1/2(z-1)-(z-3)=1/3(z+3)+1/2

Reorder the terms in parentheses
+( + 0.5z-0.5)-(z-3)=0.33333333333333*(z+3) + 0.5

Remove unnecessary parentheses
 + 0.5z-0.5-(+z-3+)=0.33333333333333+*(+z+3+) + 0.5

Remove unnecessary parentheses
 + 0.5z-0.5-1z+3=0.33333333333333*(z+3) + 0.5

Reorder the terms in parentheses
 + 0.5z-0.5-1z+3=+( + 0.33333333333333z+1) + 0.5

Remove unnecessary parentheses
 + 0.5z-0.5-1z+3=0.33333333333333z+1 + 0.5

We move all terms containing z to the left and all other terms to the right. 
 + 0.5z-1z-0.33333333333333z=+1 + 0.5 + 0.5-3

We simplify left and right side of the equation. 
-0.83333333333333z=-1

We divide both sides of the equation by -0.83333333333333 to get z. 
z=1.2

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